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sin(x−π)=−sin(x)
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yep, thats true, do you need to prove it?
if so, use \(\Large \sin (a-b) = \sin a \cos b - \cos a \sin b\) and plug in, a =x and b = \(\bbox[yellow]\pi\)
What are you allowed to use?
As I am sure the one you posted is used to prove the one that was given...
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