Question

Which of the following logarithmic equations has no solution?


log4(x + 2) = log4(6 - x)


log4(-x) = 1


log4(x + 2) = 1


log4(x+2) = log4(x+6)

Answer 1

try to solve for x
hint:hint: \[\huge\rm log_b a=\log_b c\]
\[\large\rm \cancel{log_b} a=\cancel{\log_b }c\]
a=c

Answer 2

bases of the log are same both sides so you cancel out log_B

Answer 3

oh so it would just be x+2=6-x

Answer 4

also try finding the log of -4 on your calculator

Answer 5

- or the log of any negative for that matter

Answer 6

for
2nd)
3rd) you need to convert log to exponential form
after that you can plugin the x value to check ur answer