A spinner and 6 cards are shown below:
A spinner with 3 equal sectors is shown in the figure. The colors Green, Blue, and Red are marked on it. The arrow points at the green color. Six cards are shown on the right side. The colors Purple, Green, Red, Yellow, Blue, and Pink are marked on them.
Jordan spins the spinner and picks up a card without looking. What is the probability that the spinner stops at green and a yellow card is selected? Answers are 1/36 , 1/18 , 1/6 1/3 I think its one 1/6?
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jimthompson5910 (jim_thompson5910):
what's the probability the spinner lands on green
OpenStudy (anonymous):
not sure
jimthompson5910 (jim_thompson5910):
probability the spinner lands on green = (# of green spaces)/(# of total spaces)
OpenStudy (anonymous):
8
jimthompson5910 (jim_thompson5910):
you have 3 sectors and only 1 green out of the three
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OpenStudy (anonymous):
ok
jimthompson5910 (jim_thompson5910):
probability the spinner lands on green = ??
jimthompson5910 (jim_thompson5910):
it will be a fraction
OpenStudy (anonymous):
1/3
jimthompson5910 (jim_thompson5910):
yes
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jimthompson5910 (jim_thompson5910):
now what is the probability of picking a yellow card?
OpenStudy (anonymous):
hmm 1
jimthompson5910 (jim_thompson5910):
it will be a fraction
jimthompson5910 (jim_thompson5910):
probability of picking yellow card = (# of yellow cards)/(# of cards total)
OpenStudy (anonymous):
1/6
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jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
now multiply the two probabilities 1/3 and 1/6
OpenStudy (anonymous):
1/18
jimthompson5910 (jim_thompson5910):
correct
OpenStudy (anonymous):
yes thank you some much jim!!
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