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If \[\cos 9\alpha = \sin \alpha \] and \[9\alpha < 90 \] degree
use the phase shift: \(sin(\alpha) = cos(90^o - \alpha)\)
|dw:1439189984579:dw|
its to find \[\tan 5\]
@UsukiDoll help pls
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tan 5
\[\tan 5 \alpha \]
@midhun.madhu1987 help
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