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What is the solution of log2x + 3125 = 3? a. x = 1 over 3 b. x = 1 c. x = 7 over 3 d. x = 4
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hey
hi there! i was just about to tag you.
\[\huge\rm log_2 x +3125 =3\] first) move the 3125 to the right side 2nd) convert log to exponential form
thats right. do you know how to convert to exponential form?
\[\log_{2}x = -3122 \]
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okay, i'm on the right track
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