A bag has 4 green pencils and 8 blue pencils. If someone reaches into the bag and randomly removes 2 pencils, what is the probability that both are not green ?PLZ HELP !!!

Question

anonymous · Answer

P is(1- (8/12))*(1-(7/11))

anonymous · Answer

I dont understand nick123457

anonymous · Answer

@nick1234567

anonymous · Answer

because pro of not happing is 1-prob and then fill in the prob= P(blue penci) for both times

anonymous · Answer

does that help?

anonymous · Answer

No

anonymous · Answer

okay well the prob of getting a blue pencil is 8/12 correct?

anonymous · Answer

There are 12 pencils in total should I subtract 2 ?

anonymous · Answer

what are the options?

anonymous · Answer

Yeah the probability of getting a blue is 8/12

anonymous · Answer

What should I do now ? @nick1234567

anonymous · Answer

so for the first pencil the prob of not getting green is (8/12) correct?

anonymous · Answer

Yeah

anonymous · Answer

so take that * the prob of not getting blue or getting green (same thing) the next time which is 7/11

anonymous · Answer

so 8/12 * 7/11 =answer

anonymous · Answer

Kk thank u so much I really appreciate it :) @ nick1234567

anonymous · Answer

anytime glad i could help!!!

anonymous · Answer

@nick1234567 I multiped it & got 56/132