Question

Sid brought $200 to the amusement park . The cost of admission is $16.25, and the cost of a lunch is $6.50. After Sid purchased an admission ticket and a lunch ticket for each person in his group, he had $18.25 left. How many people are Sid's group?
For my answer i Got that theres 7 people in his group Can someone check to see if im correct/accurate

Answer 1

i do not think it's 7 cause when i multiplied and added everything up it wasn't 7

Answer 2

I'll let x represent the number of people
6.50x+16.25x=200-18.25
22.75x=181.75
x=181.75/22.75
X=8
I think I did the math right

Answer 3

For the answer choices 8 isn't one of them @taramgrant0543664

Answer 4

given:
Sid brought $200 to the park and had only $18.25 left so $181.75 was spent
price of admission is $16.25
for a sack lunch it's $6.50
so $16.25+$6.50 = $22.75. per person hmmmmmm.

Answer 5

181.75/22.75 = 7.98901
the problem is that there is no such thing as a .9 person. -_-!
round that number up and it's approx. 8 ???

Answer 6

what about... money spent/ number of people ?
181.75 / 4 = 45.44
181.75 / 5 = 36.35
181.75 / 6 = 30.29
181.75 / 7 = 25.96

Answer 7

To be honest I think the answer is 7

Answer 8

181.75/7.9 = 23.00
181.75/8 = 22.71875 = 22.72

if there were 7 people, that guy will still have some spare change
$25.96 - 22.75 = $3.21

Answer 9

maybe it's one of those common core guestimating problems.

Answer 10

I really don't know there's probably a error in this problem

Answer 11

Let's go to a different problem

Answer 12

I've read that common core problem have guestimates as answers as opposed to the real thing
like for example we all know that 3 x 5 = 15
but according to common core 3 x 4 is 13 or something like that what the heck?!

Answer 13

x = 181.75/22.75 = 7.98901

181.75/7.98901 = 22.75000 = 22.75
but a .98 person doesn't make sense. so .. 7 will have to be the closest if we had to respect the answer choices. a la carte common core