can anyone check my work?
A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% of the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?

Question

can anyone check my work?
A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% of the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?

anonymous · Answer

1st shot     2nd shot      total
miss:       40%            5%          45% 
make:      60%           95%        155%
total:       100%         100%       200%
 
probability of missing both free throws = 45%

mathstudent55 · Answer

The probability of missing the first shot is 40%.
When she misses the first shot, the probability of missing the second shot is very, very low, only 5%.
That means that the probability of missing both shots must be much smaller than the probability of missing the first shot.

40/100 * 5/100

anonymous · Answer

0.02?

mathstudent55 · Answer

Yes, it's 0.02 which is equal to 2%.