Question

can anyone check my work?
A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% of the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?

Answer 1

1st shot 2nd shot total
miss: 40% 5% 45%
make: 60% 95% 155%
total: 100% 100% 200%

probability of missing both free throws = 45%

Answer 2

The probability of missing the first shot is 40%.
When she misses the first shot, the probability of missing the second shot is very, very low, only 5%.
That means that the probability of missing both shots must be much smaller than the probability of missing the first shot.

40/100 * 5/100

Answer 3

0.02?

Answer 4

Yes, it's 0.02 which is equal to 2%.