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Mathematics 6 Online
OpenStudy (anonymous):

Scarlett is trying to find the height of a dam. She stands 90 meters away from the dam and records the angle of elevation to the top of the dam to be 26º. Scarlett's height is 1.65 meters, so the height of the dam is

OpenStudy (anonymous):

help please

OpenStudy (anonymous):

|dw:1439257182092:dw|

OpenStudy (anonymous):

this is why tangent was invented btw you have \[\frac{x}{90}=\tan(26)\] so \[x=90\times \tan(26)\]

OpenStudy (anonymous):

use a calculator, then add \(1.65\)

OpenStudy (anonymous):

I still don't understand

OpenStudy (anonymous):

tangent is "opposite over adjacent" right?

OpenStudy (anonymous):

you are told the "adjacent' it is 90m you are looking for the "opposite" the height

OpenStudy (anonymous):

multiply 90*26

OpenStudy (anonymous):

no dear not by 26, but rather by the tangent of 26

OpenStudy (anonymous):

\[x=90\times \tan(26)\] you need a calculator for this

OpenStudy (anonymous):

43.8

OpenStudy (anonymous):

i get \(43.9\) rounded then don't forget to add her height

OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i=90tan%2826%29

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