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let cos theta = x so replace all cos with x \[\huge\rm (x-x)^2+(x+x)^2\] now solve
how did you get D ?
try again... you don't have to use a calculator it's just like (2-2)^2+ (2+2)^2
16?
do you mean (2-2)^2+(2+2)^2 = 16 ??
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Yeah
yeah right ...
\[\huge\rm \color{ReD}{(x-x)^2}+(x+x)^2\] now solve x-x= ?? x+x= ?? solve the parentheses
x-x=0 x+x=2x
yes right \[\huge\rm \color{ReD}{(0)^2}+(2x)^2= ??\]
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2x(2x)=4x^2
So the answer is B?
yes right now replace x with cos theta = answer
Thank you!
my pleasure
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Hey Vera its me starlord6200
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