Question

help please

Answer 1

b

Answer 2

how ?

Answer 3

\[I _{o} \cos ^{2} \theta =I _{t}\]

Answer 4

by squaring b/s

Answer 5

taking \[I _{o}\] to LHS

Answer 6

put theta =45' means cos theta = \[\frac{ 1 }{ \sqrt{2} }\]

Answer 7

square \[\frac{ 1 }{ \sqrt{2}}\]

Answer 8

you get 1/2=0.5

Answer 9

then get required ans

Answer 10

got it?

Answer 11

yea i got it