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OpenStudy (anonymous):
The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X:
The figure shows a circle with points A and B on it and point C outside it. Side BC of triangle ABC intersects the circle at point X. A tangent to the circle at point A is drawn from point C. Arc AB measures 100 degrees and angle CBA measures 42 degrees
What is the measure of angle ACB?
OpenStudy (anonymous):
OpenStudy (anonymous):
What is the measure of angle ACB?
29°
8°
16°
21°
OpenStudy (anonymous):
@mathstudent55
OpenStudy (anonymous):
@DJJo can u help me plz
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OpenStudy (anonymous):
or @Abbs__ can u help
OpenStudy (anonymous):
@phi
OpenStudy (anonymous):
can u help anybody plz ill give medal
OpenStudy (anonymous):
@Abbs__
OpenStudy (anonymous):
@hype.child they aren't helping today idk y
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OpenStudy (djjo):
use the inscribed angle theorem to get
AX = 2*(angle CBA)
AX = 2*42
AX = 84 degrees
OpenStudy (djjo):
now use the formula
angle ACB = (1/2)*(arc AB - arc AX)
angle ACB = (1/2)*(100 - 84)
angle ACB = ?
OpenStudy (anonymous):
is it 16 @DJJo
OpenStudy (djjo):
angle ACB = (1/2)*(arc AB - arc AX)
angle ACB = (1/2)*(100 - 84)
angle ACB = (1/2)*16
angle ACB = ?
what is 16 times 1/2?
OpenStudy (anonymous):
is it 8
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OpenStudy (djjo):
Yes
OpenStudy (anonymous):
thank u and u save m life
OpenStudy (djjo):
np
OpenStudy (anonymous):
and tbh ur cute
OpenStudy (anonymous):
the answer is 8
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