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fan and medal include steps plz 0=8x^2 number of real number solutions
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the only solution is x = 0
how did you get that?
well what happnens if you replace x with 0 the equation is \[8 \times 0^2 \] and multiplying anything by 0 is 0 the other parts.... 8 can't be 0..... and the answer when squaring something is dependant on what you are squaring...
ok thnx
but that not what i needed
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what do you need..?
0 is a real number
i needed the number of solutions
1 solution... x= 0
well in actual fact there are 2 solutions.... both zero since its a degree 2 polynomial the degree or power of the leading term determines the number of solutions... the can be real or imaginary in your question they are both real
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