Question

fan and medal
plz include steps
number of real-number solutions
0=4x^2+9
i tried mathway but couldnt find the topic

Answer 1

@nincompoop

Answer 2

\(4x^2+9 = 0 \rightarrow 4x^2 + 9 \color{red}{-9} = 0 \color{red}{-9} \)
\(4x^2 = -9 \)
then
\(\large \frac{4x^2}{\color{red}{4}} = \frac{-9}{\color{red}{4}} \rightarrow x^2 = \frac{-9}{4}\)
solve for x by obtaining the square root of both sides
it will give you the solutions

Answer 3

That seems right

Answer 4

i still dont get its confusing

Answer 5

It seems that way but it's really not

Answer 6

can you help me?

Answer 7

@isaac4321

Answer 8

He pretty much got it under control I'm terrible at explaining stuff