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OpenStudy (anonymous):
Consider the same system of blocks from the Forces Assessment (shown below). In this case, there is friction between the 5.00 kg block and tabletop. The coefficient of kinetic friction is 0.25.
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OpenStudy (anonymous):
OpenStudy (anonymous):
@Astrophysics
OpenStudy (anonymous):
whats the formula for friction?
OpenStudy (anonymous):
Oh hey Z bay formula for kinetic friction is like this (6.0kg-0.25*5.00kg)*(9.8m/s^2)=11kg(a) I think but not 100% sure
OpenStudy (anonymous):
So you got tension minus the force of friction. no angles so you can leave out trig looks good to me
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