Question

let log of PN6; log of MN=8; what is the value

Answer 1

No P/N and M/N

Answer 2

ok
\[\ln (p/n) = 6, \ln (m/n) = 8\]

Answer 3

What's the relationship ? Is it M=100P

Answer 4

using the log property ..... log a - log b = log(a/b)

\[\ln p - \ln n = 6 \rightarrow \ln n = \ln p - 6\]
\[\ln m - \ln n = 8\]

using substitution
\[\ln m - (\ln p - 6) = 8\]
\[\ln m - \ln p = 2\]
\[\ln (m/p) = 2\]
.... assuming log base 10, then yes
m/p = 100 or m = 100p