Question

Help Please Algebra 1

Answer 1

Part A: Solve A = 9 over 2(x + 23) for x. (4 points)
Part B: Determine the value of x when A = 108. (2 points)
Part C: Solve –np – 90 > 30 for n. Show your work. (4 points)

Answer 2

can you write the whole thing out =.= i don't understand

Answer 3

thats the who thing

Answer 4

here

Answer 5

okay okay :3 got cha

Answer 6

may i ask what chapter is this?

Answer 7

module 2 2.10

Answer 8

er.... what was that @.@

Answer 9

?

Answer 10

okay, you want me just give you the results or what

Answer 11

yea

Answer 12

A = -23

B = 1

C : –np – 90 > 30
-np > 120

Answer 13

-n > 120/p
n < -120/p

Answer 14

okay so for part A : you should get like this:
A= 9/2 times (x+23)
A=9/2 times x + 207/2
A= 9x +207
A=x =23
Part B:
you got A = 108 so,
108 = 9x+207
9x=-99
x=-11
Part C:
-np-90>30
-np-60>0
-np>60
np<-60
n<-60 over P

hope it help :)

Answer 15

ok thanks

Answer 16

ur welcome :)