Question

How do I solve this system??
Y=-x+3
Y=3/2x-2

Answer 1

equate the 2 equations and solve..

Answer 2

1/2x+1?

Answer 3

now bring the x" to one side of the equation...like..
-x+x+3+2=3/2x+x-2+2
3+2=3/2x+x

Answer 4

No this doesn't make sense

Answer 5

All I know is the answer is 2,1 but idk how to get it

Answer 6

\[-x+3=\frac{ 3 }{ 2 }x-2\]\[-x+3+2=\frac{ 3 }{ 2 }x\]\[-x+5=\frac{ 3 }{ 2 }x\]\[5=\frac{ 5 }{ 2 }x\]\[5/\frac{ 5 }{ 2 }=x\]\[2=x\]

Answer 7

now sub x=2 into equation 1 or 2 to get y value

Answer 8

using equation 1 we get
y=-x+3
y=-(2)+3
y=-2+3
y=1

Answer 9

so yes the answer is (2,1)