Timothy is re-arranging his marble collection.he has five identical blue marbles,five identical green marbles and three identical black marbles he can fit exactly five marbles into a case and must have at least one of each.How many different ways can he arrange the case in?

Question

decentnabeel · Answer

@ganeshie8

decentnabeel · Answer

@hartnn

decentnabeel · Answer

@mathmate  @mathmate

decentnabeel · Answer

any one you can help me

decentnabeel · Answer

@welshfella  can you slove it

welshfella · Answer

its been a long time. I could do it by listing all the combinations I suppose but there must be a quicker way.

anonymous · Answer

thanks for posting the question. As @welshfella says it gives us a chance to test our knowledge

anonymous · Answer

I am going to summarize the problem as follows:
5 identical blue marbles
5 identical green marbles
3 identical black marbles
he can fit 5 identical marbles into a case and must have at least one of each
How many different ways can he arrange the case in

anonymous · Answer

There are a total of 18! (18 factorial possible permutations) here, but we shall work our way down!

anonymous · Answer

The best way to think of this is to create 5 boxes! one for each marble

mathmate · Answer

@BPDlkeme234 
sorry to interrupt, there is a total of (5+5+3)=13 marbles only!  :)

anonymous · Answer

thatnkyou @mathlete, I had to make corrections anyway

usukidoll · Answer

so.... 13 factorial?

anonymous · Answer

If the first box has to contain a blue marble then you have a choice of 5 marbles
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