Question

6|6-4x|=8x+4

Answer 1

x= 1 or x= 5/2

Answer 2

How did you get that answer.

Answer 3

6|6-4x|=8x+4
divide both sides by 6
|6-4x|=8/6x+4/6
now
square both sides
16x^2 - 48x + 36 = (16x^2)/9 + (16x)/9 + 4/9
now make one side = 0
then solve

Answer 4

\(\Large 6|6-4x|=8x+4\)

\(\Large |6-4x|=\frac86x+\frac46\)

\(\Large \sqrt{(6-4x)^2}=\frac86x+\frac46\)

\(\Large (~~\sqrt{(6-4x)^2}~~)^2=(~~\frac86x+\frac46~~)^2\)

\(\Large (6-4x)^2=\frac{16}9x^2 + \frac{16}9x + \frac49\)

\(\Large 16x^2 - 48x + 36=\frac{16}9x^2 + \frac{16}9x + \frac49\)

\(\Large \frac{144}9x^2 - \frac{432}9x + \frac{324}9=\frac{16}9x^2 + \frac{16}9x + \frac49\)

\(\Large \frac{128}9x^2 - \frac{448}9x + \frac{320}9=0\)

\(\Large 128x^2 - 448x + 320=0\)

\(\Large 2x^2 - 7x + 5=0\)

solve for x