Question

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Answer 1

This is a closed interval, you know by the brackets meaning it doesnt include 1 ot 0 therefore answer is:

0 < (x + y) <1

Answer 2

ok, but i dont see how this helps me find the expected value, there are infinite possibilities for the value of x and y... right?

Answer 3

which is just what I said, the value of (x+y) lies in the range between 0 and 1 but does not include 0 or 1

Answer 4

sorry, i dont completely understand.

Answer 5

Hey!