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Mathematics 10 Online
OpenStudy (anonymous):

Pizza Time has collected data about customer pizza topping preferences. They have calculated that P(pepperoni) = 0.7, P(olives) = 0.6, and P(pepperoni or olives) = 0.8. Determine the P(pepperoni and olives). 0.4 0.5 0.6 0.7 I'm confused on how to solve this.

OpenStudy (anonymous):

Do you think you could maybe help me again @phi ?

OpenStudy (anonymous):

\[P(A\cup B)=P(A)+P(B)-F(A\cap B)\]

OpenStudy (anonymous):

So P(A∪B) = 0.7 + 0.6 - 0.8?

OpenStudy (anonymous):

\[.8=.7+.6-x\]solve for\(x\)

OpenStudy (anonymous):

yeah right, what you said

OpenStudy (anonymous):

OH, had it backwards

OpenStudy (anonymous):

So 0.5! Thank you!

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