Question

can anyone help me please!!!

Answer 1

http://learn.flvs.net/webdav/educator_algebraI_v20/module04/pop/04_05_assessment/04_05_assessment_popd.htm

Answer 2

i need help with 1 - 7

Answer 3

1. Ben=f(x)=2∗(3)x

Answer 4

2.Carter=f(x)=10∗(2)^x

Answer 5

what about 3-7?? @ms.hi

Answer 6

4.Amber=f(x)=3∗(4)^x Ben=f(x)=2∗(3)x Carter=f(x)=10∗(2)^x On 3rd day : Amber=f(3)=3∗(4)^3 = 192 Ben=f(x)=2∗(3)^3 = 54 Carter=f(x)=10∗(2)^3 = 80 On 10th day : Amber=f(10)=3∗(4)^10 = 3145728
Ben=f(10)=2∗(3)^10 = 118098
Carter=f(10)=10∗(2)^10 = 10240
Amber's shares are increasing by 4 times each day where as Carter's shares are only increasing by 2 times each day. So Amber's shares are expected to be more on day 10 compared to Carter's

Answer 7

5.This graph compares to the original graph of Amber’s photo share is both of them are exponential growths. The new function goes 45 units up from the original function which was f(x)=3(4)^x

Answer 8

6.Notice that Amber has started with just 3 shares and Carter started with 10 shares. Still Carter's shares are very low compared to Amber on day 10. Amber's shares are increasing by 4 times each day where as Carter's shares are only increasing by 2 times each day. So Amber's shares are expected to be more on day 10 compared to Carter's

Answer 9

Are these questions from a test?

Answer 10

no for a project @pooja195

Answer 11

thank you @ms.hi but do you know how to graph because i'm not that good at it?

Answer 12

thats ok thank you any ways:) @ms.hi

Answer 13

https://www.desmos.com/calculator/3t1miijac8 heres the graph