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system of equation y=x^2+3 y=x+5
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if anyone could show me the steps?
We generally use one to solve the other. Start with simplest. y = x + 5 y(-5) = x+ 5 (-5) y- 5 = x therefore substituting in eq .1 we get: y = (y-5)^2 +3 y = (y^2 -10y +25) + 3 y = y^2 -10y + 22 subtract y from both sides to get: 0 = y^2 -9y + 22 solve to get: |dw:1439459437832:dw|
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