Mathematics
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OpenStudy (anonymous):
ES ESTE DERECHO?
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OpenStudy (anonymous):
Why would it not be?
OpenStudy (anonymous):
its right?
OpenStudy (anonymous):
si
OpenStudy (anonymous):
nice pic of B-53 BOMBER
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OpenStudy (anonymous):
What rule did you use to solve it?
OpenStudy (anonymous):
GUESS
OpenStudy (anonymous):
Puedes Hablar Espanol?
OpenStudy (anonymous):
Not a very reliable method.
OpenStudy (anonymous):
Si esta correcto
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OpenStudy (anonymous):
si
OpenStudy (anonymous):
si lo hablo mejor que tu
OpenStudy (anonymous):
soy española
OpenStudy (anonymous):
anyways, did you find it by doing 90-40?
OpenStudy (anonymous):
no
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OpenStudy (anonymous):
i let juses take the handel
OpenStudy (anonymous):
@Robert136 You are Spanish?! Cool
OpenStudy (anonymous):
mezclado si
OpenStudy (anonymous):
did you do x+40=90
OpenStudy (anonymous):
As heretohelpalways noted, you can find the angle at k, which is the corresponding angle above labeled x.
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OpenStudy (anonymous):
also angles made by traversals between two parallel lines are all the same across all
OpenStudy (anonymous):
¿Puedo abrir una nueva pregunta
OpenStudy (anonymous):
disparalo
OpenStudy (anonymous):
@Robert136 oh, that's cool, I'm mixed too-Russian and Filipino
OpenStudy (anonymous):
cool!
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OpenStudy (anonymous):
sure- you can ask a question on a new post
OpenStudy (anonymous):
@Robert136 Do you speak fluent spanish?
OpenStudy (anonymous):
asi es amigo
OpenStudy (anonymous):
mi tercero idioma
OpenStudy (anonymous):
tu ruso también no
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OpenStudy (anonymous):
I know more Spanish than Russian