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I need help .-. Factor completely 169x^2 − 64. A (13x + 8)(13x − 8) B (13x + 8)^2 C (13x − 8)^2 D 13x − 8
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difference of squares \[\huge\rm a^2-b^2=(a+b)(a-b)\]
I think it is A
\[\sqrt{169} = 13\]
\[169x ^{2}-64 = 13^{2}x ^{2}-8^{2}\]
So as to what Nnesha explained it is going to be answer A
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okie thanks! :)
anytym @ckallerid
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