Question

graph the parabola, mark the focus and directrix on graph. y=1/32x2

help please?

Answer 1

Idk how to graph parabolas

Answer 2

@LynFran

Answer 3

@bullkidd

Answer 4

@Vocaloid

Answer 5

do you have answer choices?

Answer 6

no i need to graph it.

Answer 7

the vertex is (m,k) and p is the distance to both the focus AND the directrix along the axis of symmetry from the vertex (in opposite direction). (focus is in the same direction as the sign of p)

Answer 8

http://www.regentsprep.org/regents/math/algebra/ac4/lpara.htm

Answer 9

y= 1/32 x^2
=32y = x^2
=4(8)y = x^2

Answer 10

so given the vertex is at (0,0) and the axis of symmetry is x=0 then:
the focus is (0,8)
directrix is y = -8

Answer 11

what does this look like on a graph? i did it on my calculator and its hard to tell

Answer 12

http://www.wolframalpha.com/input/?i=y%3D1%2F32x%5E2

Answer 13

thank you