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Solve 3|2-x|≥12 x ≤ -2 or x ≥ 6 x ≥ 2 and x ≤ 6 x ≤ -2 x ≥ 6
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er???? what do you need ?
@Loser66
i think its x</= -2
how do you got 2 and 6? @.@
\[3|2-x|\ge 12\]\[|2-x|\ge 12/3\]\[|2-x|\ge4\]
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-x>/= 2 divide by -1 x</= -2
\[|2-x|\ge 4\]\[2-x \ge \pm 4\]\[2-x \ge 4\]and \[2-x \ge -4\]
\[-x \ge 4-2\]\[-x \ge 2\]\[x \le 2\] and \[-x \ge -4-2\]\[-x \ge -6\]\[x \le 6\]
error shd be \[x \le-2\]
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