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Need help The vertex of the graph of a quadratic function is (2, –1) and the y-intercept is (0, 7). Which of the following is the equation of the function? A. y=2x^2-8x+7 B. y=2x^2+8x+7 C. y=2x^2+8x-7 D. y=2x^2-7x+8
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couple ways to do this probably the easiest is to start with in in vertex form since the vertex is \((2,-1)\) it will be\[y=a(x-2)^2-1\]
all you need is \(a\) since \((0,7)\) is on the graph, put \(x=0\) and \(y=7\) solve \[7=a(0-2)^2-1\] for \(a\)
a=2
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