Question

Coordinates for D. (?,6) C is (10,0)
Rectangle ABCD.
A(2,14)
B(-2,8)
C(10,0)
D(?,6)

Answer 1

@jim_thompson5910

Answer 2

earlier we found line BC to be
\[\Large y = -\frac{2}{3}x+\frac{20}{3}\]

Answer 3

Yes, would it be the same for AD?

Answer 4

no

Answer 5

but the same steps will be used

find the slope of AD (since it's parallel to BC, the two slopes are equal). Then use it to find the equation of line AD

Answer 6

you also need the equation for line CD

Answer 7

For AD equation, would it start like: y-14=m(x-2)? m = slope

Answer 8

yes and m = -2/3 because AD and BC have the same slope (they are parallel lines)

Answer 9

So, then I can plug in 6 to get the x value for D?

Answer 10

not quite

Answer 11

you'll need equation CD

Answer 12

oh wait, nvm

Answer 13

yes you can plug in y = 6. I didn't see D(?,6)

Answer 14

Yeah, sorry, with my packet, I have image of it showing the C point being on 0. So, helped me determine the distance for the AD y and what to subtract.

Answer 15

-2/3 * -2 would be 12/3?

Answer 16

-2/3 * -2 = 4/3

Answer 17

6-14=-2/3(x-2)
-8=-2/3x + 4/3
It ends up being: 6 = -2/3x + 28/3 right?

Answer 18

good

Answer 19

now solve for x

Answer 20

x=5?

Answer 21

no

Answer 22

oh I see what went wrong

Answer 23

When you went from -8=-2/3x + 4/3 to 6 = -2/3x + 28/3 you made an error

the 6 in ` 6 = -2/3x + 28/3` should be 0

so you should have 0 = -2/3x + 28/3

Answer 24

it's 0 because you added 8 to both sides

the -8 and +8 combine to 0 on the left side

Answer 25

OH. x=14

Answer 26

yep D is (14,6)

Answer 27

To be honest, I read my graph wrong aswell, so I was confused. I lack in graphing, but all is well. You really helped and taught me a few things, I hope to remember. (:

Answer 28

I'm glad I was of help