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Mathematics 10 Online
OpenStudy (anonymous):

How many 3-digit numerical passwords are there if a digit cannot be repeated

OpenStudy (anonymous):

Hey dude

OpenStudy (anonymous):

This is a typical permutation problem

OpenStudy (anonymous):

lol im not that smart what that mean ??

OpenStudy (anonymous):

no worries homie I am here to help you

OpenStudy (anonymous):

lol ok

OpenStudy (anonymous):

It's a numerical combination right

OpenStudy (anonymous):

ig

OpenStudy (anonymous):

and there are 10 choices at first. 9 choices after, and 8 choices after

OpenStudy (anonymous):

This means you can pick a digit out of 10, and for the second number out of 9, and for third number out of 8. know what I mean?

OpenStudy (anonymous):

Dude im sooooooooooo LOST !!

OpenStudy (anonymous):

alright dude no problem I'll walk you through

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

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OpenStudy (anonymous):

Can you see the entire thing

OpenStudy (anonymous):

bro you see all that?

OpenStudy (anonymous):

yah

OpenStudy (anonymous):

So you understand?

OpenStudy (anonymous):

well is the answer umm 3 idk bruh

OpenStudy (anonymous):

The answer is that there are 720 ways to make a 3 digit long password.

OpenStudy (anonymous):

Because that's calculated with 10*9*8=720

OpenStudy (anonymous):

You have 10 options for the first digit, 9 options for the second digit, and 8 option for the first digit..... Right?

OpenStudy (anonymous):

OOOOOOOOOOOOOOOOOOOOOOOOOH OK THX BRO

OpenStudy (anonymous):

You got it bro!

OpenStudy (anonymous):

You got that flash eh?

OpenStudy (anonymous):

Yeah

OpenStudy (anonymous):

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