Mathematics
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OpenStudy (anonymous):
How many 3-digit numerical passwords are there if a digit cannot be repeated
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OpenStudy (anonymous):
Hey dude
OpenStudy (anonymous):
This is a typical permutation problem
OpenStudy (anonymous):
lol im not that smart what that mean ??
OpenStudy (anonymous):
no worries homie I am here to help you
OpenStudy (anonymous):
lol ok
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OpenStudy (anonymous):
It's a numerical combination right
OpenStudy (anonymous):
ig
OpenStudy (anonymous):
and there are 10 choices at first. 9 choices after, and 8 choices after
OpenStudy (anonymous):
This means you can pick a digit out of 10, and for the second number out of 9, and for third number out of 8. know what I mean?
OpenStudy (anonymous):
Dude im sooooooooooo LOST !!
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OpenStudy (anonymous):
alright dude no problem I'll walk you through
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
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OpenStudy (anonymous):
Can you see the entire thing
OpenStudy (anonymous):
bro you see all that?
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OpenStudy (anonymous):
yah
OpenStudy (anonymous):
So you understand?
OpenStudy (anonymous):
well is the answer umm 3 idk bruh
OpenStudy (anonymous):
The answer is that there are 720 ways to make a 3 digit long password.
OpenStudy (anonymous):
Because that's calculated with 10*9*8=720
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OpenStudy (anonymous):
You have 10 options for the first digit, 9 options for the second digit, and 8 option for the first digit..... Right?
OpenStudy (anonymous):
OOOOOOOOOOOOOOOOOOOOOOOOOH OK THX BRO
OpenStudy (anonymous):
You got it bro!
OpenStudy (anonymous):
You got that flash eh?
OpenStudy (anonymous):
Yeah
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OpenStudy (anonymous):
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