Question

3x^2=2x=2x+7

Answer 1

too many equal signs

Answer 2

HI!!

Answer 3

is it
\[3x^2-2x=2x+7\]?

Answer 4

3x2 - 2x = 2x + 7 ⇒ x=2.333 , x=-1 am I right

Answer 5

no

Answer 6

wat did I do wrong

Answer 7

\[\frac{7}{3}\neq 2.333\]

Answer 8

@misty1212 the problem is 3x^2-2x=2x+7

Answer 9

subtract \(2x+7\) from both sides to set it equal to zero, and solve\[3x^2-4x-7=0\] by factoring

Answer 10

i am bad at factoring, but i think it factors as
\[(3x-7)(x+1)=0\]

Answer 11

as a matter of fact, i am sure it does

Answer 12

yes the answers are right because my teacher gives us the answers but we have to show the work and she doesn't really teach us so i never know who to do the homework

Answer 13

are you asking how to factor it?

Answer 14

Were you taught to use the quadratic formula?

Answer 15

or how to solve ?
once you have
\[(3x-7)(x+1)=0\] set each factor equal to zero and solve for \(x\)
so
\[x+1=0\\
x=-1\] and
\[3x-7=0\\
3x=7\\
x=\frac{7}{3}\]

Answer 16

thats what i did and i got the answers right

Answer 17

So, everything's okay Cheyenne?