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Mathematics 7 Online
OpenStudy (adamaero):

Probability - 3 players, each has 15 cards (the rest of the cards are away, mucked); what's the chance one player has has all four aces? 52 cards including mucked

OpenStudy (adamaero):

Ideas?

OpenStudy (triciaal):

idea only 4/52 = x/45 where x is the probability of 4 aces each person 15 cards choose 4 aces 3 people consider arrangements for the 1 with 4 aces

OpenStudy (triciaal):

what does mucked mean?

OpenStudy (adamaero):

mucked cards are in the discarded pile

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