Question

HELP PLEASE DON'T GET IT

A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% of the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?

Answer 1

@phi please help me

Answer 2

you multiply the probability of missing the first times prob of missing the 2nd

what is the prob of missing the first?

Answer 3

40%

Answer 4

yes, or 0.4

what is the prob of missing the 2nd?
(and we have to assume we missed the first, because we are looking for the prob of missing both)

Answer 5

5% or 0.05

Answer 6

now multiply 0.4*0.05

Answer 7

you get 0.02 or 2%

Answer 8

yes

Answer 9

so that is the answer 2%

Answer 10

yes

Answer 11

thank for helping me