Question

this right?

Answer 1

https://gyazo.com/a750cd3fdc73f594885c0a6ad62e4ba2

Answer 2

i got 64/49

Answer 3

@keshaun455 one sec

Answer 4

\(\bf \left( \cfrac{\cancel{8}\cdot 4\cdot 2}{\cancel{8}\cdot 7} \right)^2\cdot \left(\cfrac{8^0}{7^{-3}} \right)^3\cdot 7^{-9}\implies \left( \cfrac{4\cdot 2}{7} \right)^2\cdot \left( \cfrac{1}{7^{-3}} \right)^{\color{blue}{ 3}}\cdot \cfrac{1}{7^9}
\\ \quad \\
\left( \cfrac{8}{7} \right)^2\cdot \cfrac{1^{1\cdot {\color{blue}{ 3}}}}{7^{-3\cdot {\color{blue}{ 3}}}}\cdot \cfrac{1}{7^9}\implies \cfrac{64}{49}\cdot \cfrac{1}{7^{-9}}\cdot \cfrac{1}{7^9}
\\ \quad \\
\cfrac{64}{49}\cdot \cfrac{1\cdot 1}{7^{-9}\cdot 7^9}\implies
\cfrac{64}{49}\cdot \cfrac{1}{7^{-9+9}}\implies ?\)

Answer 5

well. what would that give you @keshaun455 ?

Answer 6

what's is \(\large 7^{-9+9}=?\)