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A hill that has a 12% grade is one that rises 12.0 m vertically for every 100.0 m of distance in the horizontal direction. At what angle is such a hill inclined above the horizontal? There is not a graph if u are wondering*
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|dw:1439973939934:dw|
Well, I am not sure if you have any restrictions here, but if you start with the equation: \[\tan(x)=0.12 \ \ \ \ \ \ \rightarrow \ \ \ \ \ \ x=\arctan(0.12)=\tan^{-1} (0.12)\approx 6.84^{o} \approx 0.119 \ radians \] Just plug it into your calculator. The function in question is the inverse tangent function.
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