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OpenStudy (anonymous):
Help plz! algebra question below
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OpenStudy (anonymous):
OpenStudy (anonymous):
substitute 2 to x in the sqrt of 200x
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so 14.14 * 2?
OpenStudy (anonymous):
no, it must be: 200*2 then solve for the sqrt of the product
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OpenStudy (anonymous):
pk
OpenStudy (anonymous):
20
OpenStudy (anonymous):
correct :)
OpenStudy (anonymous):
thx
OpenStudy (anonymous):
you are welcome :D
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