Question

Caden rolls two fair number cubes numbered from 1 to 6. He first defines the sample space, as shown below:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

Based on the sample space, what is the probability of getting a total of 6?

5/36
6/36
7/36
8/36

Answer 1

@Vocaloid

Answer 2

I think it would be 5/36 because (1,5),(2,4),(3,3),(4,2),(5,1) all equal 6

Answer 3

thanks! :)