Question

confusing math question

Answer 1

@Shalante

Answer 2

\[z=r \cos \theta+\iota r \sin \theta \]
\[r \cos \theta=2\]
\[r \sin \theta=2\sqrt{3}\]
square and add
\[r^2\left( \cos ^2\theta+\sin ^2\theta \right)=4+4*3=16\]
r=4
\[\cos \theta~and~\sin \theta ~are~both~positive.\]
\[so~ theta~ lies~in~ first~ quadrant\]
divide
\[\tan \theta=\sqrt{3}=\tan 60,\theta=60\]
z=?

Answer 3

So the answer will be 4(cos 60) + i (sin 60) ?

Answer 4

yes