Question

I have a "few" word problems. Could someone help me out? Its been awhile since Ive done one.

Answer 1

I have no examples. So please bare with me.

Answer 2

A new car worth $24,000 is depreciating in value by $3,000 per year. Complete A- B.

A. Write the formula that models the cars value, y, in dollars, after x years.

Answer 3

This is question 5.

Answer 4

A. If the car's value declines by 3000/year, then this can be represented by 3000x, and because the car originally cost 24000, the equation would be
y=24000-3000x

Answer 5

Okay

Answer 6

B. Use the formula from part A to determine after how many years the cars value will be $15,000.

Answer 7

Here, you would just plug in 15000 for y.
15000=24000-3000x
There are a number of ways you can go about solving this, but in the end x has to be isolated on one side of the equation.
Personally, I like to subtract and then divide.
First, I would subtract 24000 from both sides
-9000=-3000x
And then I divide by -3000.
3=x
So three years is your answer.

Answer 8

Okay. Thank you. Would you mind helping with a few more?

Answer 9

Sure!

Answer 10

do you know if we should assume that a month is 30 days?

Answer 11

I honestly don't know

Answer 12

@Vocaloid what do you think?

Answer 13

The help me solve this button says " Here, x is the number of times in a month the bus is used."

Answer 14

Maybe its 1.75x=30-0.75x? That would make the most sense to me.

Answer 15

Okay.. I have new numbers now since I clicked help me solve this...
1.50x= 24x- .50x

Answer 16

= 24 not 24x

Answer 17

I got x=12