Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B?

5 = square root of the quantity of x minus 6 all squared plus y minus 5 all squared
5 = square root of the quantity of x minus 5 all squared plus y minus 6 all squared
5 = square root of the quantity of x plus 6 all squared plus y plus 5 all squared
5 = square root of the quantity of x plus 5 all squared plus y plus 6 all squared

Question

Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B?

 5 = square root of the quantity of x minus 6 all squared plus y minus 5 all squared
 5 = square root of the quantity of x minus 5 all squared plus y minus 6 all squared
 5 = square root of the quantity of x plus 6 all squared plus y plus 5 all squared
 5 = square root of the quantity of x plus 5 all squared plus y plus 6 all squared

anonymous · Answer

@stacy.reed08

anonymous · Answer

ok, what there a picture or anything with this?  I'm assuming line segment is a diagonal.

anonymous · Answer

*was, not what :)

anonymous · Answer

Nope there was no picture along with this

anonymous · Answer

ok, give me a minute to think on this.  I'm a little rusty.

anonymous · Answer

ok, pretty sure you can use the distance formula...

anonymous · Answer

Yeah i was thinking the same, but i'm an absolute slug when it comes to math

anonymous · Answer

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