Question

I am timed! PLEASE Find an equation in standard form for the hyperbola with vertices at (0, ±8) and asymptotes at y equals inverse of plus minus 1 divided by 2x.

y squared over 256 minus x squared over 64 equals 1
y squared over 64 minus x squared over 256 equals 1
y squared over 64 minus x squared over 16 equals 1
y squared over 64 minus x squared over 64 equals 1

Any ideas? Estimates? Guesses? Im under a time limit..

Answer 1

@nincompoop @ganeshie8 ?

Answer 2

@jim_thompson5910 ?

Answer 3

@jaredb2000 ?

Answer 4

@iamawesome247 ?

Answer 5

@whpalmer4 ?

Answer 6

hi.

Answer 7

[y2/64 - x2/b2\]

Answer 8

and you need b2 to finish it

Answer 9

yes

Answer 10

\[y =\frac{ 1}{ 2 } x\]

Answer 11

asymptotes are

y=±1/2 x.

Answer 12

here. http://openstudy.com/study#/updates/536d2922e4b00a5ff135840a

Answer 13

it willhelpu.