Solve x2 + 4x − 12 = 0.
there are 4+ method to factor quadratic equation for this question AC method (headphone) would easy where you have to find `2` numbers when you `multiply` them you should get product of `AC` and when you `add` or subtract them you should get `middle` term
\[\huge\rm Ax^2+Bx+C=0\] a=leading coefficient b=middle term c= constant term what is a and c in that eqaution ?
equation*
x and -12 i think
nice leading coefficient is one \[\rm 1x^2+4x-12\] so what two number you should multiply to get -12 but when you add them you should get 4
am not sure
1 times -12 = -12 right but 1-12 =-11 but we need 4 now what other number you can multiply to get -12 ?
is it 2 and -6
2 should be negative cus we need POSITIVE 4 -2 times 6 =-12 6-2=4
so factors are (x + number )(x+number)
so the answer is -2 and -6
no.
not negative 6
wait do you have to solve for x or find factors ?
x
so i was right
no. factors are (x+ first number)(x+2nd number) set it equal to zero remember one of them is negativve
(x+6)(x+(-2)) now solve for x
x+(-2)= 0 x= ?
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