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Nnesha (nnesha):
there are 4+ method to factor quadratic equation
for this question AC method (headphone) would easy
where you have to find `2` numbers when you `multiply` them you should get product of `AC` and when you `add` or subtract them you should get `middle` term
Nnesha (nnesha):
\[\huge\rm Ax^2+Bx+C=0\]
a=leading coefficient
b=middle term
c= constant term
what is a and c in that eqaution ?
Nnesha (nnesha):
equation*
OpenStudy (anonymous):
x and -12 i think
Nnesha (nnesha):
nice
leading coefficient is one \[\rm 1x^2+4x-12\]
so what two number you should multiply to get -12 but when you add them you should get 4
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OpenStudy (anonymous):
am not sure
Nnesha (nnesha):
1 times -12 = -12 right
but 1-12 =-11 but we need 4 now what other number you can multiply to get -12 ?
OpenStudy (anonymous):
is it 2 and -6
Nnesha (nnesha):
2 should be negative
cus we need POSITIVE 4
-2 times 6 =-12
6-2=4
Nnesha (nnesha):
so factors are (x + number )(x+number)
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OpenStudy (anonymous):
so the answer is -2 and -6
Nnesha (nnesha):
no.
Nnesha (nnesha):
not negative 6
Nnesha (nnesha):
wait do you have to solve for x or find factors ?
OpenStudy (anonymous):
x
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OpenStudy (anonymous):
so i was right
Nnesha (nnesha):
no.
factors are (x+ first number)(x+2nd number)
set it equal to zero
remember one of them is negativve