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Geometry Help! Please!
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The 4 triangles right angled formed are congruent Let the smallest side of these = x and let the area of shaded part equal y area of each triangle = 2* x/2 = x consider one of the large rectangles y + 2x = 6 consider the shaded part which is a paralelogram the area = base * perpendicular height
area= BE * DE - x y = 2* (3 - x) y = 6 - 2x
which is the same equation as we had before! how embarrassing!! I must be missing something here.....
the area is a rhombus - so is there a formula for this in terms of the sides - or diagonals?
Yes, here is an outline of solution step1 : show that all the four triangles outside the shaded region are congruent |dw:1440259209437:dw|
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