Question

last question of the night... promise

Answer 1

In square $ABCD$, $E$ is the midpoint of $\overline{BC}$, and $F$ is the midpoint of $\overline{CD}$. Let $G$ be the intersection of $\overline{AE}$ and $\overline{BF}$. Prove that $DG = AB$.

Answer 2

all i know is that BF = AE and BCF and ABE are congruent

Answer 3

i also cannot decide if BG is perpendicular to AE... or not?

Answer 4

well this is a pretty simple question if ur using co-ordinate geometry. :)