Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(- 3, - 25), and x intercepts at x = -8 and x = 2. (Do not include the negative sign in your answer.)

y = x2 + 6x − { Blank }

Question

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(- 3, - 25), and x intercepts at x = -8 and x = 2. (Do not include the negative sign in your answer.)

y = x2 + 6x − {  Blank  }

anonymous · Answer

@David27 Do you know how to do this?

david27 · Answer

no sorry but he might know @ganeshie8

anonymous · Answer

@ganeshie8

dan815 · Answer

x intercept of -8 means the point (-8,0) is a solution
x int of 2 means the point (2,0) is a solution to your equation

dan815 · Answer

y = x2 + 6x − { Blank }
y = x2 + 6x −B
knowing that (-8,0) is a point of this parabola so, plugging that in for x,y
0=(-8)^2+ 6*(-8) -B
B=?
solve for B
you can also use the other point
(2,0)
0=2^2+6*2-B
B=?

anonymous · Answer

So solve 2^2+6*2 first?