Question

Different Lift Cases in NLM=>
(Tutorial)

Answer 1

\(\Huge\color{Blue}{Different~Lift~Cases} \)

Answer 2

in Newtons Laws of motion

Answer 3

Case 1=> Consider a lift which is moving upward with acceleration 'a' and a person is standing on the floor of lift.

The person standing on the floor of lift is under the influence of two forces
1)Normal reaction due to flor of lift
2)Weight(mg) due to Earth



Net upward force on man= N-mg
Now, N-mg=ma
Because \[F _{net}=ma\]
so,
N=mg+ma

\[N=m(g+a)\]