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Identify the axis of symmetry and vertex of f(x) = –2x^2 –2x–1. A) Axis of symmetry: x = 0.5; Vertex: (0.5, – 0.50) B) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, 0.50) C) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, – 0.50) D) Axis of symmetry: x = 0.5; Vertex: (– 0.5, – 0.50)
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here is the formula to find x-coordinate of vertex\[\rm x=\frac{ -b }{ 2a }\] x coordinate of vertex= axis of symmetry
and then substitute all x's by its value into f(x) function to find y-coordinate of the vertex
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