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Write the equation of the line that passes through (–1, 5) and has a slope of 3 in point-slope form. x + 1 = 3(y – 5) x – 5 = 3(y + 1) y – 5 = 3(x + 1) y + 1 = 3(x – 5)
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i forget the equation for point-slope form
y-y1=m(x-x1) m=slope (x,y)
\(\sf Y=mX +C\)
y-y1=m(x-x1)
so i have to use all of them?
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@abhisat they want point slope
motown use wat i wrote
i mean
now that you wrote the equation its kind of self exploratory because y-(-1)=+1 which only one answer has
|dw:1440513305569:dw|
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