Question

I need help on order of operations

Answer 1

-12/3*(-8+(-4)^2-6)+2

Answer 2

\(-12 \div 3 \times [-8+(-4)^2-6]+2\)

Start with the innermost parentheses:

\(= -12 \div 3 \times [-8+\color{red}{(-4)^2}-6]+2\)

\(= -12 \div 3 \times [-8+\color{red}{16}-6]+2\)

The brackets now become parentheses, so work inside the parentheses.

\(= -12 \div 3 \times \color{green}{(-8+16-6)}+2\)

Inside the parentheses, do additions and subtractions in the order they appear from left to right.

\(= -12 \div 3 \times \color{green}{(-8+16-6)}+2\)

\(= -12 \div 3 \times \color{green}{(8-6)}+2\)

\(= -12 \div 3 \times \color{green}{2}+2\)

Now work on multiplications and divisions in the order they appear from left to right.

\(= \color{blue}{-12 \div 3 \times 2}+2\)

\(= \color{blue}{-4 \times 2}+2\)

\(= \color{blue}{-8}+2\)

\(= -8+2\)

Finally, there is only one addition left to do.

\(= - 6\)